Wahh!! Did a water test run this morning as I always do after adding livestock and the nitrIte was 0.25ppm! I've actually done a 75% water change. Will someone check my maths based on that result for the salt neutralisation formula for if I get +ve nitrites again?
My calculation based on TTA's recommendation:
To add 10 mg/l of chloride for every ppm of nitrite in the water, use the following steps:
1. Multiply your nitrite test reading by 10. This will give you the needed mg/l of chloride you need to add.
0.25x10=2.5mg/L
2. Calculate the actual volume in litres of the water in your tank. If your volume is in gallons you must convert this into liters. (As a rule, using the advertised volume of the tank at about 85% will put you in the right ballpark.) 1 gallon = 3.875 litres
11.5L
3. Multiply the number in #1 above by the number of liters of water in #2 above to get the total number of mg of chloride you will need to add.
2.5x11.5= 28.75mg
4. Because salt is roughly 2/3 chloride, you must multiply the number calculated in #3 by 1.5. You now know how many mg of salt you should add to the water. Dividing this number by 1,000 will convert this amount to grams which are easier to weigh for most people.
28.75x1.5=43.125
43.125/1000= 0.043g
Luckily I have some jeweller's scales but they only go to 0.1g so my theory is add 0.5g which is the nearest 0.1g then mix it with a known quantity of tank water and add only 1/10th of the resulting mix which would be 0.05g.
Does this compute?.