You'll work out the answers before I give them here
The fish have been in circa 30ppm through the photoperiod. The CO2 has had to be injected non stop throughout the photoperiod to stay circa 30ppm. Why did we need to keep it running through this period?
Because it is permanently gassing off trying to return to equilibrium.
Take a sample of tank water during the photoperiod and immediately Ph test it.
Test it after 10 minutes, 20 minutes, half an hour etc. See how long it takes for the Ph to return to circa 1Ph higher than the immediate first test.
I would suggest within half an hour you will reach your conclusion, smile and stop testing.
Now you can answer the final question of whether an airstone is needed at all.
We don't actually know what percentage of the CO2 is taken by the plants and what percentage is lost. 95% loss wouldn't be a bad guess though
Some people with reactors will try and tell you that the reactor is much better at keeping CO2 within the tank. They are making the wrong correlation.
They are seeing bubbles from diffusers rising and being lost. They are not seeing any bubbles from their reactor due to the 100% diffusion. Therefore the CO2 is being lost at the same ratio.
How do they know when they can't see what is happening. the 'mist' is visible, the 100% is not, doesn't mean the same process isn't happening. I would bet that it is a little better but a fraction. Then when you consider only circa 5% is taken by the plant that fraction becomes miniscule.
However you can then come to a technical advantage of mist. Because you can see it, you can also see what is happening, where it is going, You can play with your circulation and watch the bubbles to achieve a better result. Can't do that with 100% in solution because you can't see it
I won't go into mist versus 10% ease of plant take up because that is unproven and theory at best
Do the test and post back the 0, 10, 20, 30 readings. I would do the test for oyu but I have long sold off my CO2 unit
AC