Just One Last Question On Breeding

[afireinside]

Ok, since DT is resesive, and ST is dominent, you'd need two parents with the DT gene to have DT babies, right? So that means the two babies I got from Synirr would have DT babies. Remember it's a question, and I'm months away from the actual breeding process.

 

[wuvmybetta]

No, it's not a sure thing. One of Synirrs was a DT and she got all ST,if I remember correctly.
My latest spawn came from siblings to dozens of DT's and out of 200+ fry I didn't get a single DT. It's really luck of the draw and just having the perfect combo.

 

[OhMyDog]

I'm still new to genetics myself but I think that if both of the parents are DT geno, you'd get 25% DT, 50% DT Geno, and 25% ST. If one is a DT geno and the other doesn't carry DT, then you'd get 50% DT Geno and 50% ST. If one is a DT and one is a DT geno, you'd get 50% DT geno and 50% DT.

 

[Dart]

well is DT is recessive and ST is dominant and there are no other genes at play then

and assume d is DT, and D is ST
then Synir's mother was dd and the father was DD, so all offspring would be Dd
so breeding them both together

D d
D DD Dd
d Dd dd

my really bad punette square, 75% would be ST (25%DD, 50% Dd) and 25% would be DT (25% dd)

so 25% of the offspring would be ST with no DT geno
50% of the offspring would be ST with a DT gene
25% of the offspring would be DT, so double DT gene

 

[Andie]

And while those percentages are dead on, genetically speaking, it then becomes a question of survival rate. oppositearmor, you may have that 75 percent of the spawn that are ST pheno (2/3 of them being DT geno) die off or just not hatch, leaving you with completely DT pheno. Or you may lose the 25 percent that are DT pheno and just end up with ST; all depends on who survives

 

[supersixone]

remember that it's also entirely possible that you will get all dt or no dt at all, it's just statistically not as likely. the punnett squares predict the most statistically likely outcome, but it's not going to be dead-on

 

[Auratus]

so 25% of the offspring would be ST with no DT geno
50% of the offspring would be ST with a DT gene
25% of the offspring would be DT, so double DT gene

And there is absolutly no way to tell which of the STs have the DT geno... muahahahahaaaa
Yet another one of mother nature's cruel recessive gene jokes

But... to add to that. Breeding a DT to a DT geno, or two DT genos is MUCH better then breeding DT x DT because since DT is technically a "mutant" gene... breeding two pure DTs together often results in bent spines, short bodies, or other cullworthy deformities.

 

[Synirr]

And there is absolutly no way to tell which of the STs have the DT geno... muahahahahaaaa
Yet another one of mother nature's cruel recessive gene jokes

Unless they had a DT parent, like mine
All fry of a DT parent will carry the gene.

 

[BrookeLea]

So much genetics!

 

[afireinside]

So, your saying I'm basically right (by using the punnet square)?

 

[Andie]

You are . . . numerically right However, practically speaking you may get done at all, depending on who hatches/survives and how many eggs are actually fertilized

 

[Ethos]

Since I'm terrible at maths, and I didn't understand a word you guys spoke, I shall just standf here all alone and look like a stupid little num-chuckling.
Lol, j/k
Hi OA, haven't seen you post yet since you "came back."

 

[afireinside]

You are . . . numerically right However, practically speaking you may get done at all, depending on who hatches/survives and how many eggs are actually fertilized

I know, I just needed to know if I did the punnet square right. Ok, this topic can be closed.